Sunday, August 14, 2011

A Numerical Problem from Projectile Motion

A short is fired from a gun on the top of a hill 90m high with velocity 80m/s at an angle of 30 degree with the horizontal. Find the horizontal distance between the vertical line through the gun and the ponit where the shot strikes the ground? (Shilpa asked this question)


Take Sy= -90m

ay= -g=-9.8m/s2

uy= u sin(30) =80 x 0.5 = 40m/s

Substitute in the eqn

s = ut + 0.5 at2

and find t


The horizontal distance Rx = horizontal velocity x time =  U cos (30) x time

Substitute for u and t and get the answer

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